(12-3+5k)6+4k-2(k+5)=

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Solution for (12-3+5k)6+4k-2(k+5)= equation:


(12-3+5k)6+4k-2(k+5)=0

We simplify the equation to the form, which is simple to understand 
(12-3+5k)6+4k-2(k+5)=0

Simplifying terms in parentheses
(+9+5k)*6+4k-2*(k+5)=0

Reorder the terms in parentheses
(+54+30k)+4k-2*(k+5)=0

Remove unnecessary parentheses
+54+30k+4k-2*(k+5)=0

Reorder the terms in parentheses
+54+30k+4k+(-2k-10)=0

Remove unnecessary parentheses
+54+30k+4k-2k-10=0

We move all terms containing k to the left and all other terms to the right. 
+30k+4k-2k=0-54+10

We simplify left and right side of the equation. 
+32k=-44

We divide both sides of the equation by 32 to get k. 
k=-1.375

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