(12-3a)+(-17xy+2z)=

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Solution for (12-3a)+(-17xy+2z)= equation:


Simplifying
(12 + -3a) + (-17xy + 2z) = 0

Remove parenthesis around (12 + -3a)
12 + -3a + (-17xy + 2z) = 0

Remove parenthesis around (-17xy + 2z)
12 + -3a + -17xy + 2z = 0

Solving
12 + -3a + -17xy + 2z = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -3a + -17xy + -12 + 2z = 0 + -12

Reorder the terms:
12 + -12 + -3a + -17xy + 2z = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3a + -17xy + 2z = 0 + -12
-3a + -17xy + 2z = 0 + -12

Combine like terms: 0 + -12 = -12
-3a + -17xy + 2z = -12

Add '17xy' to each side of the equation.
-3a + -17xy + 17xy + 2z = -12 + 17xy

Combine like terms: -17xy + 17xy = 0
-3a + 0 + 2z = -12 + 17xy
-3a + 2z = -12 + 17xy

Add '-2z' to each side of the equation.
-3a + 2z + -2z = -12 + 17xy + -2z

Combine like terms: 2z + -2z = 0
-3a + 0 = -12 + 17xy + -2z
-3a = -12 + 17xy + -2z

Divide each side by '-3'.
a = 4 + -5.666666667xy + 0.6666666667z

Simplifying
a = 4 + -5.666666667xy + 0.6666666667z

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