(12-3x)-2=9(7x+18)

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Solution for (12-3x)-2=9(7x+18) equation: 



(12-3x)-2=9(7x+18)

We move all terms to the left:

(12-3x)-2-(9(7x+18))=0

We add all the numbers together, and all the variables

(-3x+12)-(9(7x+18))-2=0

We get rid of parentheses

-3x-(9(7x+18))+12-2=0



We calculate terms in parentheses: -(9(7x+18)), so:

9(7x+18)

We multiply parentheses

63x+162

Back to the equation:

-(63x+162)



We add all the numbers together, and all the variables

-3x-(63x+162)+10=0

We get rid of parentheses

-3x-63x-162+10=0

We add all the numbers together, and all the variables

-66x-152=0

We move all terms containing x to the left, all other terms to the right

-66x=152

x=152/-66

x=-2+10/33

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