(12-4)+(11m+5)+(16m-20)=180

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Solution for (12-4)+(11m+5)+(16m-20)=180 equation: 



(12-4)+(11m+5)+(16m-20)=180

We move all terms to the left:

(12-4)+(11m+5)+(16m-20)-(180)=0

determiningTheFunctionDomain
(11m+5)+(16m-20)-180+(12-4)=0

We add all the numbers together, and all the variables

(11m+5)+(16m-20)-180+8=0

We add all the numbers together, and all the variables

(11m+5)+(16m-20)-172=0

We get rid of parentheses

11m+16m+5-20-172=0

We add all the numbers together, and all the variables

27m-187=0

We move all terms containing m to the left, all other terms to the right

27m=187

m=187/27

m=6+25/27

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