(12-4x)/(2x+5)=0

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Solution for (12-4x)/(2x+5)=0 equation:



(12-4x)/(2x+5)=0
Domain of the equation: (2x+5)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-5
x!=-5/2
x!=-2+1/2
x∈R
We add all the numbers together, and all the variables
(-4x+12)/(2x+5)=0
We multiply all the terms by the denominator
(-4x+12)=0
We get rid of parentheses
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3

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