(12-4x)5-(15x+8)=-18+(10x-20)

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Solution for (12-4x)5-(15x+8)=-18+(10x-20) equation: 



(12-4x)5-(15x+8)=-18+(10x-20)

We move all terms to the left:

(12-4x)5-(15x+8)-(-18+(10x-20))=0

We add all the numbers together, and all the variables

(-4x+12)5-(15x+8)-(-18+(10x-20))=0

We multiply parentheses

-20x-(15x+8)-(-18+(10x-20))+60=0

We get rid of parentheses

-20x-15x-(-18+(10x-20))-8+60=0



We calculate terms in parentheses: -(-18+(10x-20)), so:

-18+(10x-20)

determiningTheFunctionDomain
(10x-20)-18

We get rid of parentheses

10x-20-18

We add all the numbers together, and all the variables

10x-38

Back to the equation:

-(10x-38)



We add all the numbers together, and all the variables

-35x-(10x-38)+52=0

We get rid of parentheses

-35x-10x+38+52=0

We add all the numbers together, and all the variables

-45x+90=0

We move all terms containing x to the left, all other terms to the right

-45x=-90

x=-90/-45

x=+2

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