If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( z )
3*z+21 = 0
3*z+21 = 0
3*z+21 = 0
3*z+21 = 0 // - 21
3*z = -21 // : 3
z = -21/3
z = -7
z in (-oo:-7) U (-7:+oo)
(12-(4*z))/(3*z+21) = 1/3 // - 1/3
(12-(4*z))/(3*z+21)-(1/3) = 0
(12-4*z)/(3*z+21)-1/3 = 0
(3*(12-4*z))/(3*(3*z+21))+(-1*(3*z+21))/(3*(3*z+21)) = 0
3*(12-4*z)-1*(3*z+21) = 0
15-15*z = 0
(15-15*z)/(3*(3*z+21)) = 0
(15-15*z)/(3*(3*z+21)) = 0 // * 3*(3*z+21)
15-15*z = 0
15-15*z = 0 // - 15
-15*z = -15 // : -15
z = -15/(-15)
z = 1
z = 1
| (12-3x/4)=5 | | (12+x/-4)=(5x-7/3)+2 | | (12+x)/3=5 | | (12+x)/2=8 | | (12+4x-10)/2=5x-20 | | (12+2)/-4=5 | | 3-n=2 | | (11z-5)/5z-(11z+15)/5z=0 | | (11y/4)-(2y/3)=-25 | | (11x/3)-(x/1)=(x/39)-(2/13) | | (11x)/(4)=(2x)/(5) | | (11t-4)/(11t+2)=0 | | (11r+68/3)=(-3) | | (11a/4)=(2a/5) | | (11/x-4)=(7/x+4) | | (11/x)-5=(8/X)+8 | | 5+n=-4 | | log(9)7+log(9)2(x^2)=4 | | (11/12)u=(15/2) | | (11-x)+(3x-2)+(x/2)=23 | | ln(2x)-ln(x)=0 | | (11+x)/2=11.5 | | (11+9x)/(x+2)=3 | | (11)/(7x)+(1)/(2x)=(-1/14) | | e^1-4x=2 | | (10x+4)/(x-5)=4 | | (10x+2)/x=11 | | (10x+12)(x+40)*1/2=0 | | (10w-10)/7=23 | | (10t/21)-(t/3)=1 | | (10m+3/4)=6 | | (108+x)/6=20 |