(12-4z)/(21+3z)=(1/3)

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Solution for (12-4z)/(21+3z)=(1/3) equation:


D( z )

3*z+21 = 0

3*z+21 = 0

3*z+21 = 0

3*z+21 = 0 // - 21

3*z = -21 // : 3

z = -21/3

z = -7

z in (-oo:-7) U (-7:+oo)

(12-(4*z))/(3*z+21) = 1/3 // - 1/3

(12-(4*z))/(3*z+21)-(1/3) = 0

(12-4*z)/(3*z+21)-1/3 = 0

(3*(12-4*z))/(3*(3*z+21))+(-1*(3*z+21))/(3*(3*z+21)) = 0

3*(12-4*z)-1*(3*z+21) = 0

15-15*z = 0

(15-15*z)/(3*(3*z+21)) = 0

(15-15*z)/(3*(3*z+21)) = 0 // * 3*(3*z+21)

15-15*z = 0

15-15*z = 0 // - 15

-15*z = -15 // : -15

z = -15/(-15)

z = 1

z = 1

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