(12-7w)/6=(2w+1)/9

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Solution for (12-7w)/6=(2w+1)/9 equation: 



(12-7w)/6=(2w+1)/9

We move all terms to the left:

(12-7w)/6-((2w+1)/9)=0

We add all the numbers together, and all the variables

(-7w+12)/6-((2w+1)/9)=0

We calculate fractions


(-7w)/()+(-((2w+1)*6)/()=0



We calculate terms in parentheses: +(-((2w+1)*6)/(), so:

-((2w+1)*6)/(

We multiply all the terms by the denominator


-((2w+1)*6)



We calculate terms in parentheses: -((2w+1)*6), so:

(2w+1)*6

We multiply parentheses

12w+6

Back to the equation:

-(12w+6)



We get rid of parentheses

-12w-6

Back to the equation:

+(-12w-6)



We get rid of parentheses

(-7w)/()-12w-6=0

We multiply all the terms by the denominator


(-7w)-12w*()-6*()=0

We add all the numbers together, and all the variables

(-7w)-12w*()=0

We get rid of parentheses

-7w-12w*()=0

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