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(12-a)(12-a)=0
We add all the numbers together, and all the variables
(-1a+12)(-1a+12)=0
We multiply parentheses ..
(+a^2-12a-12a+144)=0
We get rid of parentheses
a^2-12a-12a+144=0
We add all the numbers together, and all the variables
a^2-24a+144=0
a = 1; b = -24; c = +144;
Δ = b2-4ac
Δ = -242-4·1·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{24}{2}=12$
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