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(12-x)*10+x=x*10(12-x)-54
We move all terms to the left:
(12-x)*10+x-(x*10(12-x)-54)=0
We add all the numbers together, and all the variables
(-1x+12)*10+x-(x*10(-1x+12)-54)=0
We add all the numbers together, and all the variables
x+(-1x+12)*10-(x*10(-1x+12)-54)=0
We multiply parentheses
x-10x-(x*10(-1x+12)-54)+120=0
We calculate terms in parentheses: -(x*10(-1x+12)-54), so:We add all the numbers together, and all the variables
x*10(-1x+12)-54
Wy multiply elements
10x^2(--54
We use the square of the difference formula
10x^2(+54
Back to the equation:
-(10x^2(+54)
x-10x-(10x^254+120=0
We add all the numbers together, and all the variables
-9x-(10x^254+120=0
We do not support expression: x^254
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