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(12-x)/5=x
We move all terms to the left:
(12-x)/5-(x)=0
We add all the numbers together, and all the variables
(-1x+12)/5-x=0
We add all the numbers together, and all the variables
-1x+(-1x+12)/5=0
We multiply all the terms by the denominator
-1x*5+(-1x+12)=0
Wy multiply elements
-5x+(-1x+12)=0
We get rid of parentheses
-5x-1x+12=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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