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(12-x)10+x=10x+(12-x)+54
We move all terms to the left:
(12-x)10+x-(10x+(12-x)+54)=0
We add all the numbers together, and all the variables
(-1x+12)10+x-(10x+(-1x+12)+54)=0
We add all the numbers together, and all the variables
x+(-1x+12)10-(10x+(-1x+12)+54)=0
We multiply parentheses
x-10x-(10x+(-1x+12)+54)+120=0
We calculate terms in parentheses: -(10x+(-1x+12)+54), so:We add all the numbers together, and all the variables
10x+(-1x+12)+54
We get rid of parentheses
10x-1x+12+54
We add all the numbers together, and all the variables
9x+66
Back to the equation:
-(9x+66)
-9x-(9x+66)+120=0
We get rid of parentheses
-9x-9x-66+120=0
We add all the numbers together, and all the variables
-18x+54=0
We move all terms containing x to the left, all other terms to the right
-18x=-54
x=-54/-18
x=+3
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