(12-x)10+x=10x+(12-x)+54

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Solution for (12-x)10+x=10x+(12-x)+54 equation: 



(12-x)10+x=10x+(12-x)+54

We move all terms to the left:

(12-x)10+x-(10x+(12-x)+54)=0

We add all the numbers together, and all the variables

(-1x+12)10+x-(10x+(-1x+12)+54)=0

We add all the numbers together, and all the variables

x+(-1x+12)10-(10x+(-1x+12)+54)=0

We multiply parentheses

x-10x-(10x+(-1x+12)+54)+120=0



We calculate terms in parentheses: -(10x+(-1x+12)+54), so:

10x+(-1x+12)+54

We get rid of parentheses

10x-1x+12+54

We add all the numbers together, and all the variables

9x+66

Back to the equation:

-(9x+66)



We add all the numbers together, and all the variables

-9x-(9x+66)+120=0

We get rid of parentheses

-9x-9x-66+120=0

We add all the numbers together, and all the variables

-18x+54=0

We move all terms containing x to the left, all other terms to the right

-18x=-54

x=-54/-18

x=+3

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