(12-x)4+12=128

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Solution for (12-x)4+12=128 equation:



(12-x)4+12=128
We move all terms to the left:
(12-x)4+12-(128)=0
We add all the numbers together, and all the variables
(-1x+12)4+12-128=0
We add all the numbers together, and all the variables
(-1x+12)4-116=0
We multiply parentheses
-4x+48-116=0
We add all the numbers together, and all the variables
-4x-68=0
We move all terms containing x to the left, all other terms to the right
-4x=68
x=68/-4
x=-17

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