(12-x)4+12=128

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Solution for (12-x)4+12=128 equation: 



(12-x)4+12=128

We move all terms to the left:

(12-x)4+12-(128)=0

We add all the numbers together, and all the variables

(-1x+12)4+12-128=0

We add all the numbers together, and all the variables

(-1x+12)4-116=0

We multiply parentheses

-4x+48-116=0

We add all the numbers together, and all the variables

-4x-68=0

We move all terms containing x to the left, all other terms to the right

-4x=68

x=68/-4

x=-17

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