(12-x)=1/3(1+4x)

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Solution for (12-x)=1/3(1+4x) equation: 



(12-x)=1/3(1+4x)

We move all terms to the left:

(12-x)-(1/3(1+4x))=0



Domain of the equation: 3(1+4x))!=0

x∈R



We add all the numbers together, and all the variables

(-1x+12)-(1/3(4x+1))=0

We get rid of parentheses

-1x-(1/3(4x+1))+12=0

We multiply all the terms by the denominator


-1x*3(4x+1))-(1+12*3(4x+1))=0

Wy multiply elements

-3x^2(4+36x(4=0

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