(12-y)+5y=40

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Solution for (12-y)+5y=40 equation: 



(12-y)+5y=40

We move all terms to the left:

(12-y)+5y-(40)=0

We add all the numbers together, and all the variables

(-1y+12)+5y-40=0

We add all the numbers together, and all the variables

5y+(-1y+12)-40=0

We get rid of parentheses

5y-1y+12-40=0

We add all the numbers together, and all the variables

4y-28=0

We move all terms containing y to the left, all other terms to the right

4y=28

y=28/4

y=7

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