(12-y)y=40

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Solution for (12-y)y=40 equation:


Simplifying
(12 + -1y) * y = 40

Reorder the terms for easier multiplication:
y(12 + -1y) = 40
(12 * y + -1y * y) = 40
(12y + -1y2) = 40

Solving
12y + -1y2 = 40

Solving for variable 'y'.

Reorder the terms:
-40 + 12y + -1y2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 12y + -1y2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
40 + -12y + y2 = 0

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -12y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + -12y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -12y + y2 = 0 + -40
-12y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
-12y + y2 = -40

The y term is -12y.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12y + 36 + y2 = -40 + 36

Reorder the terms:
36 + -12y + y2 = -40 + 36

Combine like terms: -40 + 36 = -4
36 + -12y + y2 = -4

Factor a perfect square on the left side:
(y + -6)(y + -6) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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