(12-z)-28=11-2

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Solution for (12-z)-28=11-2 equation: 



(12-z)-28=11-2

We move all terms to the left:

(12-z)-28-(11-2)=0

We add all the numbers together, and all the variables

(-1z+12)-28-9=0

We add all the numbers together, and all the variables

(-1z+12)-37=0

We get rid of parentheses

-1z+12-37=0

We add all the numbers together, and all the variables

-1z-25=0

We move all terms containing z to the left, all other terms to the right

-z=25

z=25/-1

z=-25

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