(12/(2x-4))+(1/(x-2))=7/2

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Solution for (12/(2x-4))+(1/(x-2))=7/2 equation:


D( x )

x-2 = 0

2*x-4 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

2*x-4 = 0

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in (-oo:2) U (2:+oo)

12/(2*x-4)+1/(x-2) = 7/2 // - 7/2

12/(2*x-4)+1/(x-2)-(7/2) = 0

12/(2*x-4)+1/(x-2)-7/2 = 0

(2*12*(x-2))/(2*(2*x-4)*(x-2))+(1*2*(2*x-4))/(2*(2*x-4)*(x-2))+(-7*(2*x-4)*(x-2))/(2*(2*x-4)*(x-2)) = 0

2*12*(x-2)+1*2*(2*x-4)-7*(2*x-4)*(x-2) = 0

28*x-14*x^2+56*x-56-56 = 0

84*x-14*x^2-112 = 0

84*x-14*x^2-112 = 0

14*(6*x-x^2-8) = 0

6*x-x^2-8 = 0

DELTA = 6^2-(-8*(-1)*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-6)/(-1*2) or x = (-4^(1/2)-6)/(-1*2)

x = 2 or x = 4

14*(x-2)*(x-4) = 0

(14*(x-2)*(x-4))/(2*(2*x-4)*(x-2)) = 0

(14*(x-2)*(x-4))/(2*(2*x-4)*(x-2)) = 0 // * 2*(2*x-4)*(x-2)

14*(x-2)*(x-4) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 2}

x = 4

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