(12/2x-10)+(1/x-5)=(7/2)

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Solution for (12/2x-10)+(1/x-5)=(7/2) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(12/2)*x+1/x-10-5 = 7/2 // - 7/2

(12/2)*x+1/x-(7/2)-10-5 = 0

(12/2)*x+1/x-7/2-10-5 = 0

6*x^1+1*x^-1-37/2*x^0 = 0

(6*x^2-37/2*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-37/2*x^1+1*x^0) = 0

x^1

6*x^2+(-37/2)*x+1 = 0

6*x^2+(-37/2)*x+1 = 0

DELTA = (-37/2)^2-(1*4*6)

DELTA = 1273/4

DELTA > 0

x = ((1273/4)^(1/2)-(-37/2))/(2*6) or x = (-(-37/2)-(1273/4)^(1/2))/(2*6)

x = ((1273/4)^(1/2)+37/2)/12 or x = (37/2-(1273/4)^(1/2))/12

x in { (37/2-(1273/4)^(1/2))/12, ((1273/4)^(1/2)+37/2)/12}

x in { (37/2-(1273/4)^(1/2))/12, ((1273/4)^(1/2)+37/2)/12 }

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