(12/k)=(24/k)

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Solution for (12/k)=(24/k) equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

12/k = 24/k // - 24/k

12/k-(24/k) = 0

12/k-24*k^-1 = 0

-12*k^-1 = 0 // : -12

k^-1 = 0

k naleu017Cy do O

k belongs to the empty set

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