(12/x)+x-8=0

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Solution for (12/x)+x-8=0 equation:



(12/x)+x-8=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+12/x)+x-8=0
We add all the numbers together, and all the variables
x+(+12/x)-8=0
We get rid of parentheses
x+12/x-8=0
We multiply all the terms by the denominator
x*x-8*x+12=0
We add all the numbers together, and all the variables
-8x+x*x+12=0
Wy multiply elements
x^2-8x+12=0
a = 1; b = -8; c = +12;
Δ = b2-4ac
Δ = -82-4·1·12
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*1}=\frac{4}{2} =2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*1}=\frac{12}{2} =6 $

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