(12/x)-7/(x-12)+1=0

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Solution for (12/x)-7/(x-12)+1=0 equation:


D( x )

x = 0

x-12 = 0

x = 0

x = 0

x-12 = 0

x-12 = 0

x-12 = 0 // + 12

x = 12

x in (-oo:0) U (0:12) U (12:+oo)

12/x-(7/(x-12))+1 = 0

12/x-7*(x-12)^-1+1 = 0

12/x-7/(x-12)+1 = 0

(-7*x)/(x*(x-12))+(12*(x-12))/(x*(x-12))+(1*x*(x-12))/(x*(x-12)) = 0

12*(x-12)+1*x*(x-12)-7*x = 0

x^2+5*x-12*x-144 = 0

x^2-7*x-144 = 0

x^2-7*x-144 = 0

x^2-7*x-144 = 0

DELTA = (-7)^2-(-144*1*4)

DELTA = 625

DELTA > 0

x = (625^(1/2)+7)/(1*2) or x = (7-625^(1/2))/(1*2)

x = 16 or x = -9

(x+9)*(x-16) = 0

((x+9)*(x-16))/(x*(x-12)) = 0

((x+9)*(x-16))/(x*(x-12)) = 0 // * x*(x-12)

(x+9)*(x-16) = 0

( x+9 )

x+9 = 0 // - 9

x = -9

( x-16 )

x-16 = 0 // + 16

x = 16

x in { -9, 16 }

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