(128-x)+x+52=180

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Solution for (128-x)+x+52=180 equation: 



(128-x)+x+52=180

We move all terms to the left:

(128-x)+x+52-(180)=0

We add all the numbers together, and all the variables

(-1x+128)+x+52-180=0

We add all the numbers together, and all the variables

x+(-1x+128)-128=0

We get rid of parentheses

x-1x+128-128=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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