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(128x^2)+2x=360
We move all terms to the left:
(128x^2)+2x-(360)=0
a = 128; b = 2; c = -360;
Δ = b2-4ac
Δ = 22-4·128·(-360)
Δ = 184324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184324}=\sqrt{4*46081}=\sqrt{4}*\sqrt{46081}=2\sqrt{46081}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{46081}}{2*128}=\frac{-2-2\sqrt{46081}}{256} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{46081}}{2*128}=\frac{-2+2\sqrt{46081}}{256} $
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