(12k-38)/2-2=3k

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Solution for (12k-38)/2-2=3k equation:



(12k-38)/2-2=3k
We move all terms to the left:
(12k-38)/2-2-(3k)=0
We add all the numbers together, and all the variables
-3k+(12k-38)/2-2=0
We multiply all the terms by the denominator
-3k*2+(12k-38)-2*2=0
We add all the numbers together, and all the variables
-3k*2+(12k-38)-4=0
Wy multiply elements
-6k+(12k-38)-4=0
We get rid of parentheses
-6k+12k-38-4=0
We add all the numbers together, and all the variables
6k-42=0
We move all terms containing k to the left, all other terms to the right
6k=42
k=42/6
k=7

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