(12m-4)+(11m+5)+(16m-20)=180

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Solution for (12m-4)+(11m+5)+(16m-20)=180 equation: 



(12m-4)+(11m+5)+(16m-20)=180

We move all terms to the left:

(12m-4)+(11m+5)+(16m-20)-(180)=0

We get rid of parentheses

12m+11m+16m-4+5-20-180=0

We add all the numbers together, and all the variables

39m-199=0

We move all terms containing m to the left, all other terms to the right

39m=199

m=199/39

m=5+4/39

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