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(12n+12)12n=36
We move all terms to the left:
(12n+12)12n-(36)=0
We multiply parentheses
144n^2+144n-36=0
a = 144; b = 144; c = -36;
Δ = b2-4ac
Δ = 1442-4·144·(-36)
Δ = 41472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{41472}=\sqrt{20736*2}=\sqrt{20736}*\sqrt{2}=144\sqrt{2}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-144\sqrt{2}}{2*144}=\frac{-144-144\sqrt{2}}{288} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+144\sqrt{2}}{2*144}=\frac{-144+144\sqrt{2}}{288} $
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