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(12q+7)(2q+7)=0
We multiply parentheses ..
(+24q^2+84q+14q+49)=0
We get rid of parentheses
24q^2+84q+14q+49=0
We add all the numbers together, and all the variables
24q^2+98q+49=0
a = 24; b = 98; c = +49;
Δ = b2-4ac
Δ = 982-4·24·49
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-70}{2*24}=\frac{-168}{48} =-3+1/2 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+70}{2*24}=\frac{-28}{48} =-7/12 $
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