(12x)(12x)=(16+x-2)(16+x-2)

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Solution for (12x)(12x)=(16+x-2)(16+x-2) equation: 



(12x)(12x)=(16+x-2)(16+x-2)

We move all terms to the left:

(12x)(12x)-((16+x-2)(16+x-2))=0

We add all the numbers together, and all the variables

12x12x-((x+14)(x+14))=0

We multiply parentheses ..

-((+x^2+14x+14x+196))+12x12x=0



We calculate terms in parentheses: -((+x^2+14x+14x+196)), so:

(+x^2+14x+14x+196)

We get rid of parentheses

x^2+14x+14x+196

We add all the numbers together, and all the variables

x^2+28x+196

Back to the equation:

-(x^2+28x+196)



We get rid of parentheses

-x^2-28x+12x12x-196=0

We add all the numbers together, and all the variables

-1x^2-28x+12x12x-196=0

We move all terms containing x to the left, all other terms to the right

-1x^2-28x+12x12x=196

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