(12x+14)=(3x+41)

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Solution for (12x+14)=(3x+41) equation: 



(12x+14)=(3x+41)

We move all terms to the left:

(12x+14)-((3x+41))=0

We get rid of parentheses

12x-((3x+41))+14=0



We calculate terms in parentheses: -((3x+41)), so:

(3x+41)

We get rid of parentheses

3x+41

Back to the equation:

-(3x+41)



We get rid of parentheses

12x-3x-41+14=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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