(12x+17)/(3x+1)-(2x+15)/(x+7)=16/5

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Solution for (12x+17)/(3x+1)-(2x+15)/(x+7)=16/5 equation: 



(12x+17)/(3x+1)-(2x+15)/(x+7)=16/5

We move all terms to the left:

(12x+17)/(3x+1)-(2x+15)/(x+7)-(16/5)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R





Domain of the equation: (x+7)!=0

We move all terms containing x to the left, all other terms to the right

x!=-7

x∈R



We add all the numbers together, and all the variables

(12x+17)/(3x+1)-(2x+15)/(x+7)-(+16/5)=0

We get rid of parentheses

(12x+17)/(3x+1)-(2x+15)/(x+7)-16/5=0

We calculate fractions


((12x+17)*(x+7)*5)/((3x+1)*(x+7)*5)+(-(2x+15)*(3x+1)*5)/((3x+1)*(x+7)*5)+(-16*(3x+1)*(x+7))/((3x+1)*(x+7)*5)=0



We calculate terms in parentheses: +((12x+17)*(x+7)*5)/((3x+1)*(x+7)*5), so:

(12x+17)*(x+7)*5)/((3x+1)*(x+7)*5

We multiply all the terms by the denominator


(12x+17)*(x+7)*5)

Back to the equation:

+((12x+17)*(x+7)*5))





We calculate terms in parentheses: +(-(2x+15)*(3x+1)*5)/((3x+1)*(x+7)*5), so:

-(2x+15)*(3x+1)*5)/((3x+1)*(x+7)*5

We multiply all the terms by the denominator


-(2x+15)*(3x+1)*5)

Back to the equation:

+(-(2x+15)*(3x+1)*5))





We calculate terms in parentheses: +(-16*(3x+1)*(x+7))/((3x+1)*(x+7)*5), so:

-16*(3x+1)*(x+7))/((3x+1)*(x+7)*5

We multiply all the terms by the denominator


-16*(3x+1)*(x+7))

Back to the equation:

+(-16*(3x+1)*(x+7)))



We add all the numbers together, and all the variables

((12x+17)*(x+7)*5))+(-(2x+15)*(3x+1)*5))+(-16*(3x+1)*(x=0

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