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(12x+2)=(32x)
We move all terms to the left:
(12x+2)-((32x))=0
determiningTheFunctionDomain (12x+2)-32x=0
We add all the numbers together, and all the variables
-32x+(12x+2)=0
We get rid of parentheses
-32x+12x+2=0
We add all the numbers together, and all the variables
-20x+2=0
We move all terms containing x to the left, all other terms to the right
-20x=-2
x=-2/-20
x=1/10
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