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(12x+3)=(2x+10)
We move all terms to the left:
(12x+3)-((2x+10))=0
We get rid of parentheses
12x-((2x+10))+3=0
We calculate terms in parentheses: -((2x+10)), so:We get rid of parentheses
(2x+10)
We get rid of parentheses
2x+10
Back to the equation:
-(2x+10)
12x-2x-10+3=0
We add all the numbers together, and all the variables
10x-7=0
We move all terms containing x to the left, all other terms to the right
10x=7
x=7/10
x=7/10
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