(12x+45)+(6x-3)=18

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Solution for (12x+45)+(6x-3)=18 equation: 



(12x+45)+(6x-3)=18

We move all terms to the left:

(12x+45)+(6x-3)-(18)=0

We get rid of parentheses

12x+6x+45-3-18=0

We add all the numbers together, and all the variables

18x+24=0

We move all terms containing x to the left, all other terms to the right

18x=-24

x=-24/18

x=-1+1/3

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