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(12x+8)(8x+16)=0
We multiply parentheses ..
(+96x^2+192x+64x+128)=0
We get rid of parentheses
96x^2+192x+64x+128=0
We add all the numbers together, and all the variables
96x^2+256x+128=0
a = 96; b = 256; c = +128;
Δ = b2-4ac
Δ = 2562-4·96·128
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-128}{2*96}=\frac{-384}{192} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+128}{2*96}=\frac{-128}{192} =-2/3 $
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