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(12x-3)+(2x-5)=(3x+13)
We move all terms to the left:
(12x-3)+(2x-5)-((3x+13))=0
We get rid of parentheses
12x+2x-((3x+13))-3-5=0
We calculate terms in parentheses: -((3x+13)), so:We add all the numbers together, and all the variables
(3x+13)
We get rid of parentheses
3x+13
Back to the equation:
-(3x+13)
14x-(3x+13)-8=0
We get rid of parentheses
14x-3x-13-8=0
We add all the numbers together, and all the variables
11x-21=0
We move all terms containing x to the left, all other terms to the right
11x=21
x=21/11
x=1+10/11
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