(12x-3)/4+(1/6)x-(8x-3)/2=(3-x)/2-1

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Solution for (12x-3)/4+(1/6)x-(8x-3)/2=(3-x)/2-1 equation: 



(12x-3)/4+(1/6)x-(8x-3)/2=(3-x)/2-1

We move all terms to the left:

(12x-3)/4+(1/6)x-(8x-3)/2-((3-x)/2-1)=0



Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(12x-3)/4+(+1/6)x-(8x-3)/2-((-1x+3)/2-1)=0

We multiply parentheses

x^2+(12x-3)/4-(8x-3)/2-((-1x+3)/2-1)=0

We calculate fractions


x^2+((12x-3)*2*2)/()+(-32x+12)/()+(-((-1x+3)*4)/()=0



We calculate terms in parentheses: +((12x-3)*2*2)/(), so:

(12x-3)*2*2)/(

We multiply all the terms by the denominator


(12x-3)*2*2)

We get rid of parentheses

12x-3)*2*2

We add all the numbers together, and all the variables

12x

Back to the equation:

+(12x)





We calculate terms in parentheses: +(-((-1x+3)*4)/(), so:

-((-1x+3)*4)/(

We multiply all the terms by the denominator


-((-1x+3)*4)



We calculate terms in parentheses: -((-1x+3)*4), so:

(-1x+3)*4

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)



We get rid of parentheses

4x-12

Back to the equation:

+(4x-12)



We get rid of parentheses

x^2+12x+(-32x+12)/()+4x-12=0

We multiply all the terms by the denominator


x^2*()+12x*()+(-32x+12)+4x*()-12*()=0

We add all the numbers together, and all the variables

x^2*()+12x*()+(-32x+12)+4x*()=0

We get rid of parentheses

x^2*()+12x*()-32x+4x*()+12=0

We add all the numbers together, and all the variables

x^2*()-32x+12x*()+4x*()+12=0

We move all terms containing x to the left, all other terms to the right

x^2*()-32x+12x*()+4x*()=-12

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