(12x-3/x)=2

Solution for (12x-3/x)=2 equation:

(12x-3/x)=2

We move all terms to the left:

(12x-3/x)-(2)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+12x-3/x)-2=0

We get rid of parentheses

12x-3/x-2=0

We multiply all the terms by the denominator


12x*x-2*x-3=0

We add all the numbers together, and all the variables

-2x+12x*x-3=0

Wy multiply elements

12x^2-2x-3=0

a = 12; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·12·(-3)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{37}}{2*12}=\frac{2-2\sqrt{37}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{37}}{2*12}=\frac{2+2\sqrt{37}}{24}
$