(12x-41)=(6x+31)

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Solution for (12x-41)=(6x+31) equation: 



(12x-41)=(6x+31)

We move all terms to the left:

(12x-41)-((6x+31))=0

We get rid of parentheses

12x-((6x+31))-41=0



We calculate terms in parentheses: -((6x+31)), so:

(6x+31)

We get rid of parentheses

6x+31

Back to the equation:

-(6x+31)



We get rid of parentheses

12x-6x-31-41=0

We add all the numbers together, and all the variables

6x-72=0

We move all terms containing x to the left, all other terms to the right

6x=72

x=72/6

x=12

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