(12x-5)(12x+5)=0

Solution for (12x-5)(12x+5)=0 equation:

(12x-5)(12x+5)=0

We use the square of the difference formula

144x^2-25=0

a = 144; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·144·(-25)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*144}=\frac{-120}{288}
=-5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*144}=\frac{120}{288}
=5/12
$