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(12x/3x)+2=6
We move all terms to the left:
(12x/3x)+2-(6)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+12x/3x)+2-6=0
We add all the numbers together, and all the variables
(+12x/3x)-4=0
We get rid of parentheses
12x/3x-4=0
We multiply all the terms by the denominator
12x-4*3x=0
Wy multiply elements
12x-12x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
Równanie nie ma rozwiązania
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