(12y-8)=(8y+20)

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Solution for (12y-8)=(8y+20) equation: 



(12y-8)=(8y+20)

We move all terms to the left:

(12y-8)-((8y+20))=0

We get rid of parentheses

12y-((8y+20))-8=0



We calculate terms in parentheses: -((8y+20)), so:

(8y+20)

We get rid of parentheses

8y+20

Back to the equation:

-(8y+20)



We get rid of parentheses

12y-8y-20-8=0

We add all the numbers together, and all the variables

4y-28=0

We move all terms containing y to the left, all other terms to the right

4y=28

y=28/4

y=7

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