(13+2x)+12=(x+32)

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Solution for (13+2x)+12=(x+32) equation: 



(13+2x)+12=(x+32)

We move all terms to the left:

(13+2x)+12-((x+32))=0

We add all the numbers together, and all the variables

(2x+13)-((x+32))+12=0

We get rid of parentheses

2x-((x+32))+13+12=0



We calculate terms in parentheses: -((x+32)), so:

(x+32)

We get rid of parentheses

x+32

Back to the equation:

-(x+32)



We add all the numbers together, and all the variables

2x-(x+32)+25=0

We get rid of parentheses

2x-x-32+25=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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