(13+2x)/(4x+1)=3/4

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Solution for (13+2x)/(4x+1)=3/4 equation: 


D( x )

4*x+1 = 0

4*x+1 = 0

4*x+1 = 0

4*x+1 = 0 // - 1

4*x = -1 // : 4

x = -1/4

x in (-oo:-1/4) U (-1/4:+oo)

(2*x+13)/(4*x+1) = 3/4 // - 3/4

(2*x+13)/(4*x+1)-(3/4) = 0

(2*x+13)/(4*x+1)-3/4 = 0

(4*(2*x+13))/(4*(4*x+1))+(-3*(4*x+1))/(4*(4*x+1)) = 0

4*(2*x+13)-3*(4*x+1) = 0

49-4*x = 0

(49-4*x)/(4*(4*x+1)) = 0

(49-4*x)/(4*(4*x+1)) = 0 // * 4*(4*x+1)

49-4*x = 0

49-4*x = 0 // - 49

-4*x = -49 // : -4

x = -49/(-4)

x = 49/4

x = 49/4

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