(13+x)/20-5x/2=(10+x)/5+(1-12x)/10

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Solution for (13+x)/20-5x/2=(10+x)/5+(1-12x)/10 equation:


(13+x)/20-5x/2=(10+x)/5+(1-12x)/10

We simplify the equation to the form, which is simple to understand 
(13+x)/20-5x/2=(10+x)/5+(1-12x)/10

Simplifying:
(13+x)/20-2.5x=(10+x)/5+(1-12x)/10

Reorder the terms in parentheses
( + 0.65 + 0.05x)-2.5x=(10+x)/5+(1-12x)/10

Remove unnecessary parentheses
 + 0.65 + 0.05x-2.5x=(10+x)/5+(1-12x)/10

Reorder the terms in parentheses
 + 0.65 + 0.05x-2.5x=(+2 + 0.2x)+(1-12x)/10

Remove unnecessary parentheses
 + 0.65 + 0.05x-2.5x=+2 + 0.2x+(1-12x)/10

Reorder the terms in parentheses
 + 0.65 + 0.05x-2.5x=+2 + 0.2x+( + 0.1-1.2x)

Remove unnecessary parentheses
 + 0.65 + 0.05x-2.5x=+2 + 0.2x + 0.1-1.2x

We move all terms containing x to the left and all other terms to the right. 
 + 0.05x-2.5x-0.2x+1.2x=+2 + 0.1-0.65

We simplify left and right side of the equation. 
-1.45x=+1.45

We divide both sides of the equation by -1.45 to get x. 
x=-1

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