(13-4y)/7=(19+2y)/5

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Solution for (13-4y)/7=(19+2y)/5 equation: 



(13-4y)/7=(19+2y)/5

We move all terms to the left:

(13-4y)/7-((19+2y)/5)=0

We add all the numbers together, and all the variables

(-4y+13)/7-((2y+19)/5)=0

We calculate fractions


(-4y)/()+(-((2y+19)*7)/()=0



We calculate terms in parentheses: +(-((2y+19)*7)/(), so:

-((2y+19)*7)/(

We multiply all the terms by the denominator


-((2y+19)*7)



We calculate terms in parentheses: -((2y+19)*7), so:

(2y+19)*7

We multiply parentheses

14y+133

Back to the equation:

-(14y+133)



We get rid of parentheses

-14y-133

Back to the equation:

+(-14y-133)



We get rid of parentheses

(-4y)/()-14y-133=0

We multiply all the terms by the denominator


(-4y)-14y*()-133*()=0

We add all the numbers together, and all the variables

(-4y)-14y*()=0

We get rid of parentheses

-4y-14y*()=0

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