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(13/12)x-(3/8)=(11/8)
We move all terms to the left:
(13/12)x-(3/8)-((11/8))=0
Domain of the equation: 12)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+13/12)x-(+3/8)-((+11/8))=0
We multiply parentheses
13x^2-(+3/8)-((+11/8))=0
We get rid of parentheses
13x^2-3/8-((+11/8))=0
We calculate fractions
13x^2=0
a = 13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·13·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{26}=0$
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