(13/12)x-(3/8)=(11/8)

Solution for (13/12)x-(3/8)=(11/8) equation:

(13/12)x-(3/8)=(11/8)

We move all terms to the left:

(13/12)x-(3/8)-((11/8))=0


Domain of the equation: 12)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+13/12)x-(+3/8)-((+11/8))=0

We multiply parentheses

13x^2-(+3/8)-((+11/8))=0

We get rid of parentheses

13x^2-3/8-((+11/8))=0

We calculate fractions


13x^2=0

a = 13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·13·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{26}=0$