(13/7)r-5=(6/7)r

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Solution for (13/7)r-5=(6/7)r equation:



(13/7)r-5=(6/7)r
We move all terms to the left:
(13/7)r-5-((6/7)r)=0
Domain of the equation: 7)r!=0
r!=0/1
r!=0
r∈R
Domain of the equation: 7)r)!=0
r!=0/1
r!=0
r∈R
We add all the numbers together, and all the variables
(+13/7)r-((+6/7)r)-5=0
We multiply parentheses
13r^2-((+6/7)r)-5=0
We multiply all the terms by the denominator
13r^2*7)r)-((-5*7)r)+6=0
We add all the numbers together, and all the variables
13r^2*7)r)-((-35)r)+6=0
Wy multiply elements
91r^3-35)r)+6=0
We do not support erpression: r^3

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