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(130+50)x2=130+(50x^2)
We move all terms to the left:
(130+50)x2-(130+(50x^2))=0
determiningTheFunctionDomain -(130+50x^2)+(130+50)x2=0
We add all the numbers together, and all the variables
-(130+50x^2)+180x2=0
We add all the numbers together, and all the variables
180x^2-(130+50x^2)=0
We get rid of parentheses
180x^2-50x^2-130=0
We add all the numbers together, and all the variables
130x^2-130=0
a = 130; b = 0; c = -130;
Δ = b2-4ac
Δ = 02-4·130·(-130)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67600}=260$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-260}{2*130}=\frac{-260}{260} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+260}{2*130}=\frac{260}{260} =1 $
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