(130-x)-2(x+10)=x+(x+10)+2(x+10)

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Solution for (130-x)-2(x+10)=x+(x+10)+2(x+10) equation: 



(130-x)-2(x+10)=x+(x+10)+2(x+10)

We move all terms to the left:

(130-x)-2(x+10)-(x+(x+10)+2(x+10))=0

We add all the numbers together, and all the variables

(-1x+130)-2(x+10)-(x+(x+10)+2(x+10))=0

We multiply parentheses

(-1x+130)-2x-(x+(x+10)+2(x+10))-20=0

We get rid of parentheses

-1x-2x-(x+(x+10)+2(x+10))+130-20=0



We calculate terms in parentheses: -(x+(x+10)+2(x+10)), so:

x+(x+10)+2(x+10)

We multiply parentheses

x+(x+10)+2x+20

We get rid of parentheses

x+x+2x+10+20

We add all the numbers together, and all the variables

4x+30

Back to the equation:

-(4x+30)



We add all the numbers together, and all the variables

-3x-(4x+30)+110=0

We get rid of parentheses

-3x-4x-30+110=0

We add all the numbers together, and all the variables

-7x+80=0

We move all terms containing x to the left, all other terms to the right

-7x=-80

x=-80/-7

x=11+3/7

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